A stone is thrown with speed 20 m/s at 60° above horizontal. What is its horizontal range in metres? (Take $g = 10$, $\sqrt{3} \approx 1.73$)
Answer (integer)
34
Solution
$R = \frac{u^2 \sin 2\theta}{g} = \frac{400 \sin 120°}{10} = 40 \times \frac{\sqrt{3}}{2} \approx 34.6$ m
About this question
Subject: Physics · Chapter: Kinematics · Topic: Projectile Motion
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