A stone tied to a 0.5 m string is whirled in a horizontal circle at 10 rev/s. Its centripetal acceleration is:
Solution
$\omega = 2\pi \times 10 = 20\pi$ rad/s. $a_c = \omega^2 r = 400\pi^2 \times 0.5 = 200\pi^2$ m/s².
About this question
Subject: Physics · Chapter: Kinematics · Topic: Uniform Circular Motion
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