A ball is dropped from a height of 45 m. The time taken to reach the ground is (take $g = 10$ m/s²):
Solution
$h = \frac{1}{2}gt^2 \Rightarrow 45 = 5t^2 \Rightarrow t = 3$ s.
About this question
Subject: Physics · Chapter: Kinematics · Topic: Motion in a Straight Line
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