Easy MCQ +4 / -1 PYQ · JEE Mains 2019

A particle moves in the x-y plane with velocity $\vec{v} = (3\hat{i} + 4\hat{j})$ m/s. What is the magnitude of its velocity?

  1. A 3 m/s
  2. B 4 m/s
  3. C 5 m/s Correct answer
  4. D 7 m/s

Solution

Magnitude $= \sqrt{3^2 + 4^2} = \sqrt{9+16} = \sqrt{25} = 5$ m/s

About this question

Subject: Physics · Chapter: Kinematics · Topic: Motion in a Plane

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