A particle moves in the x-y plane with velocity $\vec{v} = (3\hat{i} + 4\hat{j})$ m/s. What is the magnitude of its velocity?
Solution
Magnitude $= \sqrt{3^2 + 4^2} = \sqrt{9+16} = \sqrt{25} = 5$ m/s
About this question
Subject: Physics · Chapter: Kinematics · Topic: Motion in a Plane
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