A particle moves along a circle of radius 10 m with constant speed. It completes one revolution in 4 s. What is the magnitude of centripetal acceleration in m/s²? (Take $\pi^2 = 10$)
Answer (integer)
25
Solution
$v = \frac{2\pi r}{T} = 5\pi$ m/s. $a_c = \frac{v^2}{r} = \frac{25\pi^2}{10} = 25$ m/s²
About this question
Subject: Physics · Chapter: Kinematics · Topic: Motion in a Plane
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