Medium INTEGER +4 / -1 PYQ · JEE Advanced 2021

A particle moves along a circle of radius 10 m with constant speed. It completes one revolution in 4 s. What is the magnitude of centripetal acceleration in m/s²? (Take $\pi^2 = 10$)

Answer (integer) 25

Solution

$v = \frac{2\pi r}{T} = 5\pi$ m/s. $a_c = \frac{v^2}{r} = \frac{25\pi^2}{10} = 25$ m/s²

About this question

Subject: Physics · Chapter: Kinematics · Topic: Motion in a Plane

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