A ball is projected with speed 20 m/s at an angle of 30° with the horizontal. What is the maximum height reached? (Take $g = 10$ m/s²)
Solution
$H = \frac{u^2 \sin^2\theta}{2g} = \frac{400 \times 0.25}{20} = 5$ m
About this question
Subject: Physics · Chapter: Kinematics · Topic: Projectile Motion
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