A body is moving in a low circular orbit about a planet of mass M and radius R. The radius of the orbit can be taken to be R itself. Then the ratio of the speed of this body in the orbit to the escape velocity from the planet is:
Solution
${V_0} = \sqrt {{{GM} \over r}}$
<br><br>${V_e} = \sqrt {{{2GM} \over r}}$
<br><br>$\therefore$ $${{{V_0}} \over {{V_e}}} = \sqrt {{{GM} \over r} \times {{2GM} \over r}} = {1 \over {\sqrt 2 }}$$
About this question
Subject: Physics · Chapter: Gravitation · Topic: Satellites and Orbital Motion
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