If one wants to remove all the mass of the earth to infinity in order to break it up completely.
The amount of energy that needs to be supplied will be ${x \over 5}{{G{M^2}} \over R}$ where x is __________ (Round off to the Nearest Integer) (M is the mass of earth, R is the radius of earth, G is the gravitational constant)
Answer (integer)
3
Solution
<p>We know that binding energy of earth,</p>
<p>$BE = - {3 \over 5}{{G{M^2}} \over R}$</p>
<p>$\therefore$ Energy required to break the earth into pieces</p>
<p>$= - BE = {3 \over 5}{{G{M^2}} \over R}$ ...... (i)</p>
<p>According to question, the amount of energy that needs to be supplied is ${x \over 5}{{G{M^2}} \over R}$.</p>
<p>Comparing it with value in Eq. (i), we get,</p>
<p>$x = 3$</p>
About this question
Subject: Physics · Chapter: Gravitation · Topic: Gravitational Field and Potential
This question is part of PrepWiser's free JEE Main question bank. 129 more solved questions on Gravitation are available — start with the harder ones if your accuracy is >70%.