The time period of a satellite revolving around earth in a given orbit is 7 hours. If the radius of orbit is increased to three times its previous value, then approximate new time period of the satellite will be
Solution
<p>$T_2^2 = {\left( {{{{R_2}} \over {{R_1}}}} \right)^3}T_1^2$</p>
<p>$\Rightarrow {T_2} = {(3)^{3/2}} \times 7 \approx 5.2 \times 7$</p>
<p>${T_2} \cong 36$ hrs</p>
About this question
Subject: Physics · Chapter: Gravitation · Topic: Kepler's Laws
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