Correct formula for height of a satellite from earths surface is :
Solution
<p>$$\begin{aligned}
& T=2 \pi \sqrt{\frac{r^3}{G M}} \\
& T^2=\frac{4 \pi^2}{G M}(R+h)^3 \\
& h=\left(\frac{G M T^2}{4 \pi^2}\right)^{\frac{1}{3}}-R \\
& =\left(\frac{G M \cdot R}{R^2} \cdot \frac{T^2}{4 \pi^2}\right)^{\frac{1}{3}}-R \\
& =\left(\frac{T^2 R^2 g}{4 \pi^2}\right)^{\frac{1}{3}}-R
\end{aligned}$$</p>
About this question
Subject: Physics · Chapter: Gravitation · Topic: Satellites and Orbital Motion
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