The distance of the Sun from earth is 1.5 $\times$ 1011 m and its angular diameter is (2000) s when observed from the earth. The diameter of the Sun will be :
Solution
<p>Diameter = r $\times$ $\delta$</p>
<p>$$ = 1.5 \times {10^{11}} \times (2000) \times \left( {{1 \over {3600}}} \right) \times \left( {{\pi \over {180}}} \right)$$</p>
<p>$= 1.45 \times {10^9}$ m</p>
About this question
Subject: Physics · Chapter: Gravitation · Topic: Satellites and Orbital Motion
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