A satellite is launched into a circular orbit of radius R around earth, while a second satellite is launched into a circular orbit of radius 1.02 R. The percentage difference in the time periods of the two satellites is :
Solution
${T^2} \propto {R^3}$<br><br>$T = k{R^{3/2}}$<br><br>${{dT} \over T} = {3 \over 2}{{dR} \over R}$<br><br>$= {3 \over 2} \times 0.02 = 0.03$<br><br>% Change = 3%
About this question
Subject: Physics · Chapter: Gravitation · Topic: Kepler's Laws
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