Two satellites $\mathrm{A}$ and $\mathrm{B}$, having masses in the ratio $4: 3$, are revolving in circular orbits of radii $3 \mathrm{r}$ and $4 \mathrm{r}$ respectively around the earth. The ratio of total mechanical energy of $\mathrm{A}$ to $\mathrm{B}$ is :
Solution
<p>$U = - {{G{M_e}m} \over {2r}}$</p>
<p>So, ${{{U_A}} \over {{U_B}}} = {{{m_A}} \over {{m_B}}} \times {{{r_B}} \over {{r_A}}}$</p>
<p>$= {4 \over 3} \times {4 \over 3} = {{16} \over 9}$</p>
About this question
Subject: Physics · Chapter: Gravitation · Topic: Satellites and Orbital Motion
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