The height of any point P above the surface of earth is equal to diameter of earth. The value of acceleration due to gravity at point P will be : (Given g = acceleration due to gravity at the surface of earth).

<p>The acceleration due to gravity (g) at a distance (r) from the center of a planet is given by:</p> <p>$g = \frac{G M}{r^2}$</p> <p>where:</p> <ul> <li>G is the gravitational constant,</li> <li>M is the mass of the planet,</li> <li>r is the distance from the center of the planet.</li> </ul> <p>If the height h of a point P above the surface of the Earth is equal to the diameter of the Earth, then the distance r from the center of the Earth to the point P is 3 times the radius of the Earth. Substituting this into the equation for g gives:</p> <p>$g&#39; = g \left(\frac{R}{3R}\right)^2 = \frac{g}{9}$</p> <p>where:</p> <ul> <li>g&#39; is the acceleration due to gravity at the point P,</li> <li>R is the radius of the Earth.</li> </ul> <p>Therefore, the value of acceleration due to gravity at point P is g/9.</p>