Two planets A and B of equal mass are having their period of revolutions TA and TB such that TA = 2TB. These planets are revolving in the circular orbits of radii rA and rB respectively. Which out of the following would be the correct relationship of their orbits?
Solution
<p>${T_A} = 2{T_B}$</p>
<p>Now $T_A^2 \propto r_A^3$</p>
<p>$$ \Rightarrow {\left( {{{{r_A}} \over {{r_B}}}} \right)^3} = {\left( {{{{T_A}} \over {{T_B}}}} \right)^2}$$</p>
<p>$\Rightarrow r_A^3 = 4r_B^3$</p>
About this question
Subject: Physics · Chapter: Gravitation · Topic: Kepler's Laws
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