If the acceleration due to gravity experienced by a point mass at a height h above the surface of earth is same as that of the acceleration due to gravity at a depth $\alpha \mathrm{h}\left(\mathrm{h}<<\mathrm{R}_{\mathrm{e}}\right)$ from the earth surface. The value of $\alpha$ will be _________.
(use $\left.\mathrm{R}_{\mathrm{e}}=6400 \mathrm{~km}\right)$
Answer (integer)
2
Solution
<p>$g\left( {1 - {{2h} \over R}} \right) = g\left( {1 - {d \over R}} \right)$</p>
<p>$\Rightarrow 2h = d$</p>
<p>$\Rightarrow \alpha = 2$</p>
About this question
Subject: Physics · Chapter: Gravitation · Topic: Gravitational Field and Potential
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