"The minimum and maximum distances of a planet revolving around the sun are x1 and x2. If the minimum speed of the planet on its trajectory is v0 then its maximum speed will be :"

"Angular momentum conservation equation ${v_0}{x_2} = {v_1}{x_1}$ ${v_1} = {{{v_0}{x_2}} \\over {{x_1}}}$"

Easy MCQ +4 / -1 PYQ · JEE Mains 2021

The minimum and maximum distances of a planet revolving around the sun are x₁ and x₂. If the minimum speed of the planet on its trajectory is v₀ then its maximum speed will be :

A ${{{v_0}x_1^2} \over {x_2^2}}$
B ${{{v_0}x_2^2} \over {x_1^2}}$
C ${{{v_0}x_1^{}} \over {x_2^{}}}$
D ${{{v_0}x_2^{}} \over {x_1^{}}}$ Correct answer

Solution

Angular momentum conservation equation ${v_0}{x_2} = {v_1}{x_1}$<br><br>${v_1} = {{{v_0}{x_2}} \over {{x_1}}}$

About this question

Subject: Physics · Chapter: Gravitation · Topic: Kepler's Laws

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The minimum and maximum distances of a planet revolving around the sun are x1 and x2. If the minimum speed of the planet on its trajectory is v0 then its maximum speed will be :

Solution

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The minimum and maximum distances of a planet revolving around the sun are x₁ and x₂. If the minimum speed of the planet on its trajectory is v₀ then its maximum speed will be :