A parallel plate capacitor filled with a medium of dielectric constant 10, is connected across a battery and is charged. The dielectric slab is replaced by another slab of dielectric constant 15. Then the energy of capacitor will :
Solution
<p>$U = {1 \over 2}(k{C_0}){V^2}$</p>
<p>$\Rightarrow {{U'} \over U} = 1.5$</p>
<p>$\Rightarrow$ Energy increases by 50%</p>
About this question
Subject: Physics · Chapter: Electrostatics · Topic: Electric Potential and Capacitance
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