"The electric field in a region is given by $\overrightarrow E = {2 \over 5}{E_0}\widehat i + {3 \over 5}{E_0}\widehat j$ with ${E_0} = 4.0 \times {10^3}{N \over C}$. The flux of this field through a rectangular surface area 0.4 m2 parallel to the Y-Z plane is __________ Nm2C$-$1."

Question

Accepted Answer

"$\phi = \overrightarrow E \,.\,\overrightarrow A$

$$ = {{{E_0}} \over 5}\left( {2\widehat i + 3\widehat j} \right)\,.\,\left( {0.4\widehat i} \right)$$

$= {{4000} \over 5}\left( {2 \times 0.4} \right)$

$= 640$ Nm² C^$-$1"

The electric field in a region is given by $\overrightarrow E = {2 \over 5}{E_0}\widehat i + {3 \over 5}{E_0}\widehat j$ with ${E_0} = 4.0 \times {10^3}{N \over C}$. The flux of this field through a rectangular surface area 0.4 m² parallel to the Y-Z plane is __________ Nm²C^$-$1.

Solution

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The electric field in a region is given by $\overrightarrow E = {2 \over 5}{E_0}\widehat i + {3 \over 5}{E_0}\widehat j$ with ${E_0} = 4.0 \times {10^3}{N \over C}$. The flux of this field through a rectangular surface area 0.4 m2 parallel to the Y-Z plane is __________ Nm2C$-$1.

Solution

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The electric field in a region is given by $\overrightarrow E = {2 \over 5}{E_0}\widehat i + {3 \over 5}{E_0}\widehat j$ with ${E_0} = 4.0 \times {10^3}{N \over C}$. The flux of this field through a rectangular surface area 0.4 m² parallel to the Y-Z plane is __________ Nm²C^$-$1.