A charge of $+4\,\mu C$ is placed at origin. The electric field at a point 2 m away is:
Solution
$E = kq/r^2 = 9\times 10^9 \times 4\times 10^{-6}/4 = 9\times 10^3$ N/C.
About this question
Subject: Physics · Chapter: Electrostatics · Topic: Electric Field and Field Lines
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