A 10 μF capacitor is charged to 100 V. Energy stored is $x$ mJ. Find $x$.
Answer (integer)
50
Solution
$U = \tfrac12 CV^2 = 0.5\times 10\times 10^{-6}\times 10^4 = 0.05$ J = 50 mJ.
About this question
Subject: Physics · Chapter: Electrostatics · Topic: Electric Potential and Capacitance
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