Electric field in a certain region is given by $$\overrightarrow{\mathrm{E}}=\left(\frac{\mathrm{A}}{x^{2}} \hat{i}+\frac{\mathrm{B}}{y^{3}} \hat{j}\right) \text {. The } \mathrm{SI} \text { unit of } \mathrm{A} \text { and } \mathrm{B}$$ are :
Solution
<p>$$\overrightarrow E = \left( {{A \over {{x^2}}}\widehat i + {B \over {{y^3}}}\widehat j} \right)$$</p>
<p>$$\left[ {{A \over {{x^2}}}} \right] = [E] = \left[ {{F \over q}} \right] = \left[ {{N \over C}} \right] = N{C^{ - 1}}$$</p>
<p>$\mathrm{[A] = (N{m^2}{C^{ - 1}})}$</p>
<p>$\mathrm{[B] = N{m^3}{C^{ - 1}}}$</p>
About this question
Subject: Physics · Chapter: Electrostatics · Topic: Electric Field and Field Lines
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