Easy MCQ +4 / -1

For a charged conducting sphere of radius $R$, the field inside (at $r<R$) is:

  1. A $kQ/R^2$
  2. B $kQ/r^2$
  3. C zero Correct answer
  4. D $kQr/R^3$

Solution

All charge resides on the surface; Gaussian surface inside encloses zero charge.

About this question

Subject: Physics · Chapter: Electrostatics · Topic: Gauss's Law

This question is part of PrepWiser's free JEE Main question bank. 15 more solved questions on Electrostatics are available — start with the harder ones if your accuracy is >70%.

Drill 25 more like these. Every day. Free.

PrepWiser turns these solved questions into a daily practice loop. Chapter-wise drills, full mocks, AI doubt chat. No auto-renew.

Start free →