An electric dipole of moment
$$\overrightarrow p = \left( { - \widehat i - 3\widehat j + 2\widehat k} \right) \times {10^{ - 29}} $$ C.m is
at the origin
(0, 0, 0). The electric field due to this dipole at
$\overrightarrow r = + \widehat i + 3\widehat j + 5\widehat k$ (note that $\overrightarrow r .\overrightarrow p = 0$ ) is parallel to :
Solution
Since $\overrightarrow r$
and $\overrightarrow p$
are perpendicular to each other
therefore point lies on the equitorial plane.
Therefore electric field at the point will be
antiparallel to the dipole moment.
<br><br>$\therefore$ $\overrightarrow E || - \overrightarrow p$
<br><br>$\Rightarrow$ $\overrightarrow E ||\left( {\widehat i + 3\widehat j - 2\widehat k} \right)$
About this question
Subject: Physics · Chapter: Electrostatics · Topic: Coulomb's Law
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