Two equal capacitors are first connected in series and then in parallel. The ratio of the equivalent capacities in the two cases will be :
Solution
Given, C<sub>1</sub> = C<sub>2</sub> = C<br/><br/>When both capacitors are connected in series, their equivalent capacitance will be<br/><br/>${1 \over {{C_s}}} = {1 \over C} + {1 \over C} = {2 \over C}$<br/><br/>$\Rightarrow {C_s} = {C \over 2}$<br/><br/>When both capacitors are connected in parallel, their equivalent capacitance will be<br/><br/>C<sub>p</sub> = C + C = 2C<br/><br/>$\therefore$ The ratio of equivalent capacitance in series and parallel combination is<br/><br/>${{{C_s}} \over {{C_p}}} = {{C/2} \over {2C}} = {1 \over 4}$<br/><br/>$\therefore$ C<sub>s</sub> : C<sub>p</sub> = 1 : 4
About this question
Subject: Physics · Chapter: Electrostatics · Topic: Electric Potential and Capacitance
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