The total charge on the system of capacitors $C_{1}=1 \mu \mathrm{F}, C_{2}=2 \mu \mathrm{F}, \mathrm{C}_{3}=4 \mu \mathrm{F}$ and $\mathrm{C}_{4}=3 \mu \mathrm{F}$ connected in parallel is :
(Assume a battery of $20 \mathrm{~V}$ is connected to the combination)
Solution
<p>Equivalent $C = \sum {{C_i}}$</p>
<p>$= 10\,\mu F$</p>
<p>$\Rightarrow$ Charge $Q = CV$</p>
<p>$= 200\,\mu C$</p>
About this question
Subject: Physics · Chapter: Electrostatics · Topic: Electric Potential and Capacitance
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