Capacitance of an isolated conducting sphere of radius R1 becomes n times when it is enclosed by a concentric conducting sphere of radius R2 connected to earth. The ratio of their radii $\left( {{{{R_2}} \over {{R_1}}}} \right)$ is :
Solution
<p>Initially $= {C_0} = 4\pi {\varepsilon _0}{R_1}$</p>
<p>Finally $${{4\pi {\varepsilon _0}{R_1}{R_2}} \over {{R_2} - {R_1}}} = n{C_0} = 4\pi {\varepsilon _0}n{R_1}$$</p>
<p>$\Rightarrow$ ${{{R_2}} \over {{R_2} - {R_1}}} = n$</p>
<p>$\Rightarrow$$1 - {{{R_1}} \over {{R_2}}} = {1 \over n}$</p>
<p>$\Rightarrow$ ${{{R_1}} \over {{R_2}}} = {{n - 1} \over n}$</p>
<p>$\Rightarrow$ ${{{R_2}} \over {{R_1}}} = {n \over {n - 1}}$</p>
About this question
Subject: Physics · Chapter: Electrostatics · Topic: Electric Potential and Capacitance
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