Medium MCQ +4 / -1 PYQ · JEE Mains 2022

Capacitance of an isolated conducting sphere of radius R1 becomes n times when it is enclosed by a concentric conducting sphere of radius R2 connected to earth. The ratio of their radii $\left( {{{{R_2}} \over {{R_1}}}} \right)$ is :

  1. A ${n \over {n - 1}}$ Correct answer
  2. B ${{2n} \over {2n + 1}}$
  3. C ${{n + 1} \over n}$
  4. D ${{2n + 1} \over n}$

Solution

<p>Initially $= {C_0} = 4\pi {\varepsilon _0}{R_1}$</p> <p>Finally $${{4\pi {\varepsilon _0}{R_1}{R_2}} \over {{R_2} - {R_1}}} = n{C_0} = 4\pi {\varepsilon _0}n{R_1}$$</p> <p>$\Rightarrow$ ${{{R_2}} \over {{R_2} - {R_1}}} = n$</p> <p>$\Rightarrow$$1 - {{{R_1}} \over {{R_2}}} = {1 \over n}$</p> <p>$\Rightarrow$ ${{{R_1}} \over {{R_2}}} = {{n - 1} \over n}$</p> <p>$\Rightarrow$ ${{{R_2}} \over {{R_1}}} = {n \over {n - 1}}$</p>

About this question

Subject: Physics · Chapter: Electrostatics · Topic: Electric Potential and Capacitance

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