An electric dipole of mass $m$, charge $q$, and length $l$ is placed in a uniform electric field $\vec{E} = E_0\hat{i}$. When the dipole is rotated slightly from its equilibrium position and released, the time period of its oscillations will be :
Solution
<p>$$\begin{aligned}
& \mathrm{I} \omega 2 \theta=\mathrm{q} \ell \mathrm{E}_0 \theta \\
& 2 \mathrm{~m}\left(\frac{\ell}{2}\right)^2 \omega^2=\mathrm{q} \ell \mathrm{E}_0 \\
& \omega^2=\frac{2 \mathrm{qE}_0}{\mathrm{~m} \ell} \\
& \mathrm{~T}=2 \pi \sqrt{\frac{\mathrm{~m} \ell}{2 \mathrm{qE}_0}}
\end{aligned}$$</p>
About this question
Subject: Physics · Chapter: Electrostatics · Topic: Electric Field and Field Lines
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