If the potential barrier across a p-n junction is $0.6 \mathrm{~V}$. Then the electric field intensity, in the depletion region having the width of $6 \times 10^{-6} \mathrm{~m}$, will be __________ $\times 10^{5} \mathrm{~N} / \mathrm{C}$.
Answer (integer)
1
Solution
<p>$E = {V \over d} = {{0.6} \over {6 \times {{10}^{ - 6}}}} = 1 \times {10^5}$</p>
About this question
Subject: Physics · Chapter: Electronic Devices · Topic: p-n Junction Diode
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