A transistor is connected in common emitter circuit configuration, the collector supply voltage is 10 V and the voltage drop across a resistor of 1000 $\Omega$ in the collector circuit is 0.6 V. If the current gain factor ($\beta$) is 24, then the base current is _____________ $\mu$A. (Round off to the Nearest Integer)
Answer (integer)
25
Solution
$\beta = {{{I_C}} \over {{I_B}}} = 24;$<br><br>R<sub>C</sub> = 1000<br><br>$\Delta$V = 0.6<br><br>${I_C} = {{0.6} \over {1000}}$<br><br>I<sub>C</sub> = 6 $\times$ 10<sup>$-$4</sup><br><br>${I_B} = {{{I_C}} \over \beta } = {{6 \times {{10}^{ - 4}}} \over {24}} = 25\mu A$
About this question
Subject: Physics · Chapter: Electronic Devices · Topic: Transistors
This question is part of PrepWiser's free JEE Main question bank. 52 more solved questions on Electronic Devices are available — start with the harder ones if your accuracy is >70%.