For a transistor $\alpha$ and $\beta$ are given as $\alpha = {{{I_C}} \over {{I_E}}}$ and $\beta = {{{I_C}} \over {{I_B}}}$. Then the correct relation between $\alpha$ and $\beta$ will be :
Solution
$\alpha = {{{I_C}} \over {{I_E}}}$, $\beta = {{{I_C}} \over {{I_B}}}$; ${I_E} = {I_C} + {I_B}$<br><br>$$\alpha = {{{I_C}} \over {{I_C} + {I_B}}} = {{{I_C}/{I_B}} \over {{{{I_C}} \over {{I_B}}} + 1}} = {\beta \over {\beta + 1}}$$<br><br>$1 + {1 \over \beta } = {1 \over \alpha }$<br><br>${1 \over \beta } = {{1 - \alpha } \over \alpha }$<br><br>$\beta = {\alpha \over {1 - \alpha }}$
About this question
Subject: Physics · Chapter: Electronic Devices · Topic: Semiconductors
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