Easy MCQ +4 / -1 PYQ · JEE Mains 2021

For a transistor $\alpha$ and $\beta$ are given as $\alpha = {{{I_C}} \over {{I_E}}}$ and $\beta = {{{I_C}} \over {{I_B}}}$. Then the correct relation between $\alpha$ and $\beta$ will be :

  1. A $\alpha = {{1 - \beta } \over \beta }$
  2. B $\beta = {\alpha \over {1 - \alpha }}$ Correct answer
  3. C $\alpha \beta = 1$
  4. D $\alpha = {\beta \over {1 - \beta }}$

Solution

$\alpha = {{{I_C}} \over {{I_E}}}$, $\beta = {{{I_C}} \over {{I_B}}}$; ${I_E} = {I_C} + {I_B}$<br><br>$$\alpha = {{{I_C}} \over {{I_C} + {I_B}}} = {{{I_C}/{I_B}} \over {{{{I_C}} \over {{I_B}}} + 1}} = {\beta \over {\beta + 1}}$$<br><br>$1 + {1 \over \beta } = {1 \over \alpha }$<br><br>${1 \over \beta } = {{1 - \alpha } \over \alpha }$<br><br>$\beta = {\alpha \over {1 - \alpha }}$

About this question

Subject: Physics · Chapter: Electronic Devices · Topic: Semiconductors

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