A horizontal straight wire $5 \mathrm{~m}$ long extending from east to west falling freely at right angle to horizontal component of earths magnetic field $0.60 \times 10^{-4} \mathrm{~Wbm}^{-2}$. The instantaneous value of emf induced in the wire when its velocity is $10 \mathrm{~ms}^{-1}$ is _________ $\times 10^{-3} \mathrm{~V}$.
Answer (integer)
3
Solution
<p>$$\begin{aligned}
& \mathrm{B}_{\mathrm{H}}=0.60 \times 10^{-4} \mathrm{~Wb} / \mathrm{m}^2 \\
& \text { Induced emf e}=\mathrm{B}_{\mathrm{H}} \mathrm{v} \ell \\
&=0.60 \times 10^{-4} \times 10 \times 5 \\
&=3 \times 10^{-3} \mathrm{~V}
\end{aligned}$$</p>
About this question
Subject: Physics · Chapter: Electromagnetic Induction · Topic: Motional EMF
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