A metallic rod of length 20 cm is placed in North-South direction and is moved at a constant speed of 20 m/s towards East. The horizontal component of the Earth's magnetic field at that place is 4 $\times$ 10$-$3 T and the angle of dip is 45$^\circ$. The emf induced in the rod is ___________ mV.
Answer (integer)
16
Solution
<p>$E = Blv$</p>
<p>$= 4 \times {10^{ - 3}} \times {{20} \over {100}} \times 20$ Volts</p>
<p>$= 16$ mV</p>
About this question
Subject: Physics · Chapter: Electromagnetic Induction · Topic: Motional EMF
This question is part of PrepWiser's free JEE Main question bank. 66 more solved questions on Electromagnetic Induction are available — start with the harder ones if your accuracy is >70%.