A circular coil of radius 8.0 cm and 20 turns is rotated about its vertical diameter with an angular speed of 50 rad s$-$1 in a uniform horizontal magnetic field of 3.0 $\times$ 10$-$2 T. The maximum emf induced the coil will be ................. $\times$ 10$-$2 volt (rounded off to the nearest integer)
Answer (integer)
60
Solution
Maximum emf $\varepsilon = N\,\omega AB$<br><br>N = 20, $\omega$ = 50, B = 3 $\times$ 10<sup>$-$2</sup> T<br><br>$\varepsilon$ = 20 $\times$ 50 $\times$ $\pi$ $\times$ (0.08)<sup>2</sup> $\times$ 3 $\times$ 10<sup>$-$2</sup> = 60.28 $\times$ 10<sup>$-$2</sup><br><br>Rounded off to nearest integer = 60
About this question
Subject: Physics · Chapter: Electromagnetic Induction · Topic: Faraday's Laws
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