The magnetic flux $\phi$ (in weber) linked with a closed circuit of resistance $8 \Omega$ varies with time (in seconds) as $\phi=5 t^2-36 t+1$. The induced current in the circuit at $t=2 \mathrm{~s}$ is __________ A.
Answer (integer)
2
Solution
<p>$$\begin{aligned}
& \varepsilon=-\left(\frac{\mathrm{d} \phi}{\mathrm{dt}}\right)=10 \mathrm{t}-36 \\
& \text { at } \mathrm{t}=2, \varepsilon=16 \mathrm{~V} \\
& \mathrm{i}=\frac{\varepsilon}{\mathrm{R}}=\frac{16}{8}=2 \mathrm{~A}
\end{aligned}$$</p>
About this question
Subject: Physics · Chapter: Electromagnetic Induction · Topic: Faraday's Laws
This question is part of PrepWiser's free JEE Main question bank. 66 more solved questions on Electromagnetic Induction are available — start with the harder ones if your accuracy is >70%.