Consider I₁ and I₂ are the currents flowing simultaneously in two nearby coils 1 & 2, respectively. If L₁ = self inductance of coil 1, M₁₂ = mutual inductance of coil 1 with respect to coil 2, then the value of induced emf in coil 1 will be :

1. A <p>e₁ = -L₁$\frac{dI_2}{dt}$ - M₁₂$\frac{dI_1}{dt}$</p>
2. B <p>e₁ = -L₁$\frac{dI_1}{dt}$ + M₁₂$\frac{dI_2}{dt}$</p>
3. C <p>e₁ = -L₁$\frac{dI_1}{dt}$ - M₁₂$\frac{dI_1}{dt}$</p>
4. D <p>e₁ = -L₁$\frac{dI_1}{dt}$ - M₁₂$\frac{dI_2}{dt}$</p> Correct answer