"A metallic conductor of length 1 m rotates in a vertical plane parallel to east-west direction about one of its end with angular velocity 5 rad s$-$1. If the horizontal component of earth's magnetic field is 0.2 $\times$ 10$-$4 T, then emf induced between the two ends of the conductor is :"

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Accepted Answer

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$Emf = {1 \over 2}B\omega {l^2}$

$= {1 \over 2} \times 0.2 \times {10^{ - 4}} \times 5 \times {1^2}$ V

= 0.5 $\times$ 10^$-$4 V

= 50 $\mu$V

"

A metallic conductor of length 1 m rotates in a vertical plane parallel to east-west direction about one of its end with angular velocity 5 rad s^$-$1. If the horizontal component of earth's magnetic field is 0.2 $\times$ 10^$-$4 T, then emf induced between the two ends of the conductor is :

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A metallic conductor of length 1 m rotates in a vertical plane parallel to east-west direction about one of its end with angular velocity 5 rad s$-$1. If the horizontal component of earth's magnetic field is 0.2 $\times$ 10$-$4 T, then emf induced between the two ends of the conductor is :

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A metallic conductor of length 1 m rotates in a vertical plane parallel to east-west direction about one of its end with angular velocity 5 rad s^$-$1. If the horizontal component of earth's magnetic field is 0.2 $\times$ 10^$-$4 T, then emf induced between the two ends of the conductor is :