"The current in a coil of self inductance 2.0 H is increasing according to I = 2 sin(t2) A. The amount of energy spent during the period when current changes from 0 to 2 A is ____________ J."

" $U = {1 \\over 2}L{I^2}$ \n $= {1 \\over 2}2 \\times {2^2} = 4$ J "

Easy INTEGER +4 / -1 PYQ · JEE Mains 2022

The current in a coil of self inductance 2.0 H is increasing according to I = 2 sin(t²) A. The amount of energy spent during the period when current changes from 0 to 2 A is ____________ J.

Answer (integer) 4

Solution

<p>$U = {1 \over 2}L{I^2}$</p> <p>$= {1 \over 2}2 \times {2^2} = 4$ J</p>

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Subject: Physics · Chapter: Electromagnetic Induction · Topic: Self and Mutual Inductance

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The current in a coil of self inductance 2.0 H is increasing according to I = 2 sin(t2) A. The amount of energy spent during the period when current changes from 0 to 2 A is ____________ J.

Solution

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The current in a coil of self inductance 2.0 H is increasing according to I = 2 sin(t²) A. The amount of energy spent during the period when current changes from 0 to 2 A is ____________ J.