Match List I with List II
| List - I | List - II | ||
|---|---|---|---|
| (A) | $$\oint \vec{B} \cdot \overrightarrow{d l}=\mu_o i_c+\mu_o \varepsilon_o \frac{d \phi_E}{d t}$$ | (I) | Gauss' law for electricity |
| (B) | $\oint \vec{E} \cdot \overrightarrow{d l}=\frac{d \phi_B}{d t}$ | (II) | Gauss' law for magnetism |
| (C) | $\oint \vec{E} \cdot \overrightarrow{d A}=\frac{Q}{\varepsilon_o}$ | (III) | Faraday law |
| (D) | $\oint \vec{B} \cdot \overrightarrow{d A}=0$ | (IV) | Ampere - Maxwell law |
Choose the correct answer from the options given below:
Solution
<p>Ampere-Maxwell law</p>
<p>$$\rightarrow \oint \overrightarrow{\mathrm{B}} \cdot \overrightarrow{\mathrm{dl}}=\mu_0 \mathrm{i}_{\mathrm{c}}+\mu_0 \varepsilon_0 \frac{\mathrm{d} \phi_{\mathrm{E}}}{\mathrm{dt}}$$</p>
<p>Faraday law $$\rightarrow \oint \vec{E} \cdot \overrightarrow{d l}=\frac{d \phi_{\mathrm{B}}}{d t}$$</p>
<p>Gauss' law for electricity $$\rightarrow \oint \overrightarrow{\mathrm{E}} \cdot \overrightarrow{\mathrm{dA}}=\frac{\mathrm{Q}}{\varepsilon_0}$$</p>
<p>Gauss ' law for magnetism $\rightarrow \oint \vec{B} \cdot \overrightarrow{d A}=0$</p>
About this question
Subject: Physics · Chapter: Electromagnetic Induction · Topic: Faraday's Laws
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