Two resistors of 3 Ω and 6 Ω are connected in parallel. The equivalent resistance is:
Solution
$\frac{1}{R_{eq}} = \frac{1}{3} + \frac{1}{6} = \frac{1}{2} \Rightarrow R_{eq} = 2$ Ω
About this question
Subject: Physics · Chapter: Current Electricity · Topic: Ohm's Law and Resistance
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