In a balanced Wheatstone bridge with arms 4 Ω, 6 Ω, 10 Ω and $S$, the value of $S$ (in Ω) is:
Answer (integer)
15
Solution
$4/6 = 10/S \Rightarrow S = 15$ Ω.
About this question
Subject: Physics · Chapter: Current Electricity · Topic: Wheatstone Bridge
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