Consider an arithmetic series and a geometric series having four initial terms from the set {11, 8, 21, 16, 26, 32, 4}. If the last terms of these series are the maximum possible four digit numbers, then the number of common terms in these two series is equal to ___________.
Answer (integer)
3
Solution
A.P. from the set will be 11, 16, 21, 26 .....
<br><br>G.P. from the set will be 4, 8, 16, 32, 64, 128, 256,
512, 1024, 2048, 4096, 8192 .....
<br><br>So common terms are 16, 256, 4096.
About this question
Subject: Mathematics · Chapter: Sequences and Series · Topic: Arithmetic Progression
This question is part of PrepWiser's free JEE Main question bank. 209 more solved questions on Sequences and Series are available — start with the harder ones if your accuracy is >70%.