If the sum of an infinite GP a, ar, ar2, ar3, ....... is 15 and the sum of the squares of its each term is 150, then the sum of ar2, ar4, ar6, ....... is :
Solution
Sum of infinite terms :<br><br>${a \over {1 - r}} = 15$ ..... (i)<br><br>Series formed by square of terms :<br><br>a<sup>2</sup>, a<sup>2</sup>r<sup>2</sup>, a<sup>2</sup>r<sup>4</sup>, a<sup>2</sup>r<sup>6</sup> .......<br><br>Sum = ${{{a^2}} \over {1 - {r^2}}} = 150$<br><br>$$ \Rightarrow {a \over {1 - r}}.{a \over {1 + r}} = 150 \Rightarrow 15.{a \over {1 + r}} = 150$$<br><br>$\Rightarrow {a \over {1 + r}} = 10$ ...... (ii)<br><br>by (i) and (ii), a = 12; r = ${1 \over 5}$<br><br>Now, series : ar<sup>2</sup>, ar<sup>4</sup>, ar<sup>6</sup><br><br>Sum = $${{a{r^2}} \over {1 - {r^2}}} = {{12.\left( {{1 \over {25}}} \right)} \over {1 - {1 \over {25}}}} = {1 \over 2}$$
About this question
Subject: Mathematics · Chapter: Sequences and Series · Topic: Arithmetic Progression
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