The total number of 4-digit numbers whose greatest common divisor with 18 is 3, is _________.
Answer (integer)
1000
Solution
Let N be the four digit number<br><br>gcd(N, 18) = 3<br><br>Hence N is an odd integer which is divisible by 3 but not by 9.<br><br>4 digit odd multiples of 3<br><br>1005, 1011, ..........., 9999 $\to$ 1500<br><br>4 digit odd multiples of 9<br><br>1017, 1035, ..........., 9999 $\to$ 500<br><br>Hence number of such N = 1000
About this question
Subject: Mathematics · Chapter: Sequences and Series · Topic: Arithmetic Progression
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