Let $a, b, c>1, a^3, b^3$ and $c^3$ be in A.P., and $\log _a b, \log _c a$ and $\log _b c$ be in G.P. If the sum of first 20 terms of an A.P., whose first term is $\frac{a+4 b+c}{3}$ and the common difference is $\frac{a-8 b+c}{10}$ is $-444$, then $a b c$ is equal to :
Solution
<p>$2{b^3} = {a^3} + {c^3}$</p>
<p>$${\left( {{{\log a} \over {\log c}}} \right)^2} = \left( {{{\log b} \over {\log a}}} \right)\left( {{{\log c} \over {\log b}}} \right)$$</p>
<p>$\Rightarrow {(\log a)^3} = {(\log c)^3}$</p>
<p>$\Rightarrow \log a = \log c$</p>
<p>$\Rightarrow a = c$</p>
<p>$\Rightarrow a = b = c$</p>
<p>${T_1} = 2a,d = - {{3a} \over 5}$</p>
<p>${S_{20}} = - 444$</p>
<p>$$ \Rightarrow {{20} \over 2}\left( {2(2a) + (19)\left( { - {{3a} \over 5}} \right)} \right) = - 444$$</p>
<p>$\Rightarrow 10{{(20a - 57a)} \over 5} = - 444$</p>
<p>$\Rightarrow 37a = 222$</p>
<p>$\Rightarrow a = 6$</p>
<p>$\Rightarrow abc = {(6)^3} = 216$</p>
About this question
Subject: Mathematics · Chapter: Sequences and Series · Topic: Arithmetic Progression
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