Medium MCQ +4 / -1 PYQ · JEE Mains 2023

Let $a, b, c>1, a^3, b^3$ and $c^3$ be in A.P., and $\log _a b, \log _c a$ and $\log _b c$ be in G.P. If the sum of first 20 terms of an A.P., whose first term is $\frac{a+4 b+c}{3}$ and the common difference is $\frac{a-8 b+c}{10}$ is $-444$, then $a b c$ is equal to :

  1. A 343
  2. B 216 Correct answer
  3. C $\frac{343}{8}$
  4. D $\frac{125}{8}$

Solution

<p>$2{b^3} = {a^3} + {c^3}$</p> <p>$${\left( {{{\log a} \over {\log c}}} \right)^2} = \left( {{{\log b} \over {\log a}}} \right)\left( {{{\log c} \over {\log b}}} \right)$$</p> <p>$\Rightarrow {(\log a)^3} = {(\log c)^3}$</p> <p>$\Rightarrow \log a = \log c$</p> <p>$\Rightarrow a = c$</p> <p>$\Rightarrow a = b = c$</p> <p>${T_1} = 2a,d = - {{3a} \over 5}$</p> <p>${S_{20}} = - 444$</p> <p>$$ \Rightarrow {{20} \over 2}\left( {2(2a) + (19)\left( { - {{3a} \over 5}} \right)} \right) = - 444$$</p> <p>$\Rightarrow 10{{(20a - 57a)} \over 5} = - 444$</p> <p>$\Rightarrow 37a = 222$</p> <p>$\Rightarrow a = 6$</p> <p>$\Rightarrow abc = {(6)^3} = 216$</p>

About this question

Subject: Mathematics · Chapter: Sequences and Series · Topic: Arithmetic Progression

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