Medium INTEGER +4 / -1 PYQ · JEE Mains 2023

The sum to $20$ terms of the series $2 \cdot 2^{2}-3^{2}+2 \cdot 4^{2}-5^{2}+2 \cdot 6^{2}-\ldots \ldots$ is equal to __________.

Answer (integer) 1310

Solution

$$ \begin{aligned} & \sum_{r=1}^{10}\left(2 \cdot(2 r)^2-(2 r+1)^2\right) \\\\ & =\sum_{r=1}^{10}\left(8 r^2-4 r^2-4 r-1\right) \\\\ & =\sum_{r=1}^{10}\left(4 r^2-4 r-1\right) \\\\ & =\frac{4 \cdot 10 \cdot 11 \cdot 21}{6}-4 \frac{10 \cdot 11}{2}-10 \\\\ & =44 \cdot 35-220-10 \\\\ & =1540-230=1310 \end{aligned} $$

About this question

Subject: Mathematics · Chapter: Sequences and Series · Topic: Arithmetic Progression

This question is part of PrepWiser's free JEE Main question bank. 209 more solved questions on Sequences and Series are available — start with the harder ones if your accuracy is >70%.

Drill 25 more like these. Every day. Free.

PrepWiser turns these solved questions into a daily practice loop. Chapter-wise drills, full mocks, AI doubt chat. No auto-renew.

Start free →