The sum to $20$ terms of the series $2 \cdot 2^{2}-3^{2}+2 \cdot 4^{2}-5^{2}+2 \cdot 6^{2}-\ldots \ldots$ is equal to __________.
Answer (integer)
1310
Solution
$$
\begin{aligned}
& \sum_{r=1}^{10}\left(2 \cdot(2 r)^2-(2 r+1)^2\right) \\\\
& =\sum_{r=1}^{10}\left(8 r^2-4 r^2-4 r-1\right) \\\\
& =\sum_{r=1}^{10}\left(4 r^2-4 r-1\right) \\\\
& =\frac{4 \cdot 10 \cdot 11 \cdot 21}{6}-4 \frac{10 \cdot 11}{2}-10 \\\\
& =44 \cdot 35-220-10 \\\\
& =1540-230=1310
\end{aligned}
$$
About this question
Subject: Mathematics · Chapter: Sequences and Series · Topic: Arithmetic Progression
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