Easy MCQ +4 / -1 PYQ · JEE Mains 2020

If the first term of an A.P. is 3 and the sum of its first 25 terms is equal to the sum of its next 15 terms, then the common difference of this A.P. is :

  1. A ${1 \over 4}$
  2. B ${1 \over 5}$
  3. C ${1 \over 7}$
  4. D ${1 \over 6}$ Correct answer

Solution

First 25 terms = a, a + d, .......,a + 24d <br><br>Next 15 terms = a + 25d, a + 26d, ......, a + 39d <br><br>$\therefore$ $${{25} \over 2}\left[ {2a + 24d} \right] = {{15} \over 2}\left[ {2\left( {a + 25d} \right) + 14d} \right]$$ <br><br>$\Rightarrow$ 50a + 600d = 15 [2a + 50d + 14d] <br><br>$\Rightarrow$ 20a + 600d = 960d <br><br>$\Rightarrow$ 60 = 360d <br><br>$\Rightarrow$ d = ${1 \over 6}$

About this question

Subject: Mathematics · Chapter: Sequences and Series · Topic: Arithmetic Progression

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