The sum of all those terms, of the arithmetic progression 3, 8, 13, ...., 373, which are not divisible by 3, is equal to ____________.
Answer (integer)
9525
Solution
The sum of all those terms, of the arithmetic progression $3,8,13 \ldots, 373$.
<br/><br/>Which are not divisible by 3 is
<br/><br/>$$
\begin{aligned}
& =(3+8+13+18+\ldots+373) -(3+18+33+\ldots+363) \\\\
& =\frac{75}{2}(3+373)-\frac{25}{2}(3+363) \\\\
& =\frac{75}{2} \times 376-\frac{25}{2} \times 366 \\\\
& =75 \times 188-25 \times 183 \\\\
& =14100-4575 \\\\
& =9525
\end{aligned}
$$
About this question
Subject: Mathematics · Chapter: Sequences and Series · Topic: Arithmetic Progression
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