Easy MCQ +4 / -1 PYQ · JEE Mains 2022

The sum $\sum\limits_{n = 1}^{21} {{3 \over {(4n - 1)(4n + 3)}}}$ is equal to

  1. A $\frac{7}{87}$
  2. B $\frac{7}{29}$ Correct answer
  3. C $\frac{14}{87}$
  4. D $\frac{21}{29}$

Solution

<p>$$\sum\limits_{n = 1}^{21} {{3 \over {(4n - 1)(4n + 3)}} = {3 \over 4}\sum\limits_{n = 1}^{21} {{1 \over {4n - 1}} - {1 \over {4n + 3}}} } $$</p> <p>$$ = {3 \over 4}\left[ {\left( {{1 \over 3} - {1 \over 7}} \right) + \left( {{1 \over 7} - {1 \over {11}}} \right) + \,\,....\,\, + \,\,\left( {{1 \over {83}} - {1 \over {87}}} \right)} \right]$$</p> <p>$$ = {3 \over 4}\left[ {{1 \over 3} - {1 \over {87}}} \right] = {3 \over 4}{{84} \over {3.87}} = {7 \over {29}}$$</p>

About this question

Subject: Mathematics · Chapter: Sequences and Series · Topic: Arithmetic Progression

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