The interior angles of a polygon with n sides, are in an A.P. with common difference 6°. If the largest interior angle of the polygon is 219°, then n is equal to _______.
Answer (integer)
20
Solution
<p>$$\begin{aligned}
& \frac{\mathrm{n}}{2}(2 \mathrm{a}+(\mathrm{n}-1) 6)=(\mathrm{n}-2) \cdot 180^{\circ} \\
& \mathrm{an}+3 \mathrm{n}^2-3 \mathrm{n}=(\mathrm{n}-2) \cdot 180^{\circ}\quad\text{.... (1)}
\end{aligned}$$</p>
<p>Now according to question</p>
<p>$$\begin{aligned}
& a+(n-1) 6^{\circ}=219^{\circ} \\
& \Rightarrow a=225^{\circ}-6 n^{\circ}\quad\text{.... (2)}
\end{aligned}$$</p>
<p>Putting value of a from equation (2) in (1)</p>
<p>We get</p>
<p>$$\begin{aligned}
& \left(225 \mathrm{n}-6 \mathrm{n}^2\right)+3 \mathrm{n}^2-3 \mathrm{n}=180 \mathrm{n}-360 \\
& \Rightarrow 2 \mathrm{n}^2-42 \mathrm{n}-360=0 \\
& \Rightarrow \mathrm{n} 2-14 \mathrm{n}-120=0 \\
& \mathrm{n}=20,-6 \text { (rejected) }
\end{aligned}$$</p>
About this question
Subject: Mathematics · Chapter: Sequences and Series · Topic: Arithmetic Progression
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